Question

in ABC AB=AC ans the bisector of A intersect BC at D prove that ADB=ADC​

Answer 1

Answer:

By SAS ∆ADB is congruent to ∆ADC

Step-by-step explanation:In ∆ADB and ∆ADC,

AB = AC (given)

Angle BAD = Angle CAD

AD = AD (common)

So by SAS congruence rule ∆ ADB is similar to ∆ ADC

Answer 2

Step-by-step explanation:

Ray AD is the bisector of angle A

angle BAD=angleDAC ........(1)

In triangle ADB and ADC

angle BAD=angle DAC ........from 1

Side AB = side AC........given

side AD= side AD......common side

hence triangle ADB is congruent to triangle ADC

hence angle ADB =angleADC......(c.a.c.t.)