In ΔABC, AD is the bisector of ∠BAC. Prove that AB > BD.
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Assume a triangle as in the figure ,with angles α,β&2θ.
Angle BAC, is 2θ.
Now ,we know that in a triangle ,the side which faces the bigger angle is bigger.
Angle BAC, is 2θ.
Now ,we know that in a triangle ,the side which faces the bigger angle is bigger.
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