In ∆ABC, AD is the median to side BC, E is a point on AD such that AE=ED. If ar{∆ ABC} = 144 cm2 find ar{∆DEC}.
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in triangle ABC AD is median
⇒ar[ABD]=ar[ADC]
⇒ar[ADC]=1/2 ar[ABC] [i]
also CE is median
⇒ar[DEC]=1/2 ar[ADC]
⇒ar[DEC]=1/2 * 1/2 ar[ABC] from equation [i]
⇒ar[DEC]=1/4ar[ABC]
=1/4*144
= 36 cm ^2
⇒ar[ABD]=ar[ADC]
⇒ar[ADC]=1/2 ar[ABC] [i]
also CE is median
⇒ar[DEC]=1/2 ar[ADC]
⇒ar[DEC]=1/2 * 1/2 ar[ABC] from equation [i]
⇒ar[DEC]=1/4ar[ABC]
=1/4*144
= 36 cm ^2
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