In ∆ ABC, AD is the perpendicular bisector of BC show that ∆ ABC in an isosceles triangle in which AB=AC.
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In ∆ ABC, AD is the perpendicular bisector of BC. To Prove: A ABC is an isosceles triangle in which AB = AC. ∴ AB = AC | C.P.C.T. ∴ ∆ABC is an isosceles triangle in which AB = AC.
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