In ∆ ABC, AD is the Perpendicular bisector of BC show that ∆ ABC in an isosceles triangle in AB=AC.
Answers
Answered by
10
Answer:
mark me as brainlist m....
Attachments:
Answered by
3
Answer:
In AOB and AOC,
BD = CD [AD bisects BC]
ADB = ADC = [AD BC]
AD = AD [Common]
ABD ACD [By SAS congruency]
AB = AC [By C.P.C.T.]
Therefore, ABC is an isosceles triangle.
Similar questions