Question

in ABC B=70 C=80 The bisector of A intersect BC at BC at D then find ADB and ADC​

Answer 1

Answer:

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Answer 2

∠ADC​ = 85°

∠ADB = 95°

Step-by-step explanation:

in a triangle ABC

<A + <B + <C =180 °

<A + 70 + 80 = 180 °

so <A  = 30°

bisector of <A intersect BC

so < BAD = <DAC = 15°

now in triangle ABD

∠A + ∠B +∠D = 180°

∠15 +∠70 +∠D = 180°

∠D = 95° or ∠ADB = 95°

now ∠ADB +∠ADC​ = 180° ( straight line sum)

∠ADC​ + 95 = 180 °

or ∠ADC​ = 85°