In ABC if 2angleA=3angleB=angleC equal to 3 angle b is equal to 6 angle C determine angle A ,B and ,C.
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Answered by
6
Heya !!
It seems something is wrong in your question.
Correct question : In a triangle ABC 2 Angle A = 3 Angle B = 6 Angle C . determine angle A , B and C.
Solution : Let 2 /_ A = 3 /_ B = 6/_ C = X°.
Then,
/_ A = ( X/2 )° , /_ B = ( X/3)° and /_ C = (X/6)°.
Therefore,
/_ A + /_ B + /_ C = 180° [ Sum of three angle of a triangle is always equal to 180° ]
X/2 + X/3 + X/6 = 180
=> 3X + 2X + X = 180 × 6
=> 6X = 1080
=> X = 1080/6
=> X = 180
/_ A = ( X/2)° = ( 180/2)° = 90°
/_ B = (X/3)° = (180/3)° = 60°
And,
/_ C = ( X/6)° = (180/6) = 30°.
It seems something is wrong in your question.
Correct question : In a triangle ABC 2 Angle A = 3 Angle B = 6 Angle C . determine angle A , B and C.
Solution : Let 2 /_ A = 3 /_ B = 6/_ C = X°.
Then,
/_ A = ( X/2 )° , /_ B = ( X/3)° and /_ C = (X/6)°.
Therefore,
/_ A + /_ B + /_ C = 180° [ Sum of three angle of a triangle is always equal to 180° ]
X/2 + X/3 + X/6 = 180
=> 3X + 2X + X = 180 × 6
=> 6X = 1080
=> X = 1080/6
=> X = 180
/_ A = ( X/2)° = ( 180/2)° = 90°
/_ B = (X/3)° = (180/3)° = 60°
And,
/_ C = ( X/6)° = (180/6) = 30°.
Answered by
2
Hey !
Let 2 /_ A = 3 /_ B = 6/_ C = X°.
angle A = ( X/2 )° , angle B = ( X/3)° and angle C = (X/6)°.
angle A +angle B + angle C = 180°
x/2 + x/3 + x/6 = 180
3x + 2x + x = 180 × 6
6x = 1080
x = 1080/6
x = 180
angle A = 90°
angle B = 60°
and
angle C = 30°.
Let 2 /_ A = 3 /_ B = 6/_ C = X°.
angle A = ( X/2 )° , angle B = ( X/3)° and angle C = (X/6)°.
angle A +angle B + angle C = 180°
x/2 + x/3 + x/6 = 180
3x + 2x + x = 180 × 6
6x = 1080
x = 1080/6
x = 180
angle A = 90°
angle B = 60°
and
angle C = 30°.
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