Question

In ∆ ABC, if a = 2, b = 3 and sin= 2/3, then
angleB = ...........
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Answer 1

Answer:

Step-by-step explanation:

we know that : sin=perpendicular/hypotenuse

so,perpendicular=2 and hypotenuse=3

we use Pythagoras theorem hypotenuse^2=perpendicular^2+base^2

3^2=2^2+base^2

base^2= 9-4

base=sqr root of 5

angle b is 3/2 or sqr root of 5/3