Question

In ∆ ABC, if PQ || side BC, AP = 6, PB = 4 and AQ = 9, then find QC.

Answer 1

Step-by-step explanation:

By Basic Proportionality Theorem

AP/ PB = AQ / QC

6/4 = 9/ QC

QC = 9×4 / 6

QC = 36/ 6

QC = 6

HERE IS YOUR ANSWER ......

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Answer 2

By basic proportionality theorem

AP/PB =AQ/QC

6/4 =9/QC

QC=9×4/6

QC=36/6

=6

QC =6

Answer is 6