In ∆ABC isosceles triangle, based on BC held the median of our era. If the perimeter is ∆ABC 64cm, the perimeter ∆ABD 52 cm, find the median length AD.
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Answer:
AP = AQ = 10 cm
Step-by-step explanation:
∆ABC is an isosceles triangle
AB = AC
Perimeter = 44 cm
Perimeter = AB + BC + AC
=> AB + 12 + AB = 44
=> 2AB = 32
=> AB = 16
AB = AC = 16 cm
AP = AQ Tangent
BP = BR Tangent
CQ = CR Tangent
AP = AB - BP = 16 - BR
AQ = AB - CQ = 16 - CR
Adding Both
AP + AQ = 32 - (BR + CR)
=> AP + AQ = 32 - BC
=> AP + AQ = 32 - 12
=> AP + AQ = 20
AP = AQ = 10
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