Question

In∆ABC,<A=60•,<60•, then​

Answer 1

$\huge\underline\mathfrak\blue{❥︎ANSWER}$

If in ∆ ABC

Angle A = 60°

B = 60°

then Angle C is =

A + B + C = 180°

60 + 60 + C = 180°

120° +C= 180°

C= 180° -120°

C= 60°

thus, ∆ ABC, is an equilateral ∆

Answer 2

Answer:

$\huge \underline \mathbb \red{answer}$

If in ∆ ABC

Angle A = 60°

B = 60°

then Angle C is =

A + B + C = 180°

60 + 60 + C = 180°

120° +C= 180°

C= 180° -120°

C= 60°

thus, ∆ ABC, is an equilateral ∆