Question

In ∆ ABC, m ∠ABC = 90°, seg BN perpendicular seg AC, AN = 9, NC = 16 then find BN. ​

Answer 1

Answer:

math ka timahi paipar ka Answer

Answer 2

Step-by-step explanation:

AB^2 = BN^2 + 9^2

BC^2 = BN^2 + 16^2

AB^2 + BC^2 = 2 BN^2 + 9^2 + 16^2

Or, AC^2 = 2 BN^2 + 337

Or, 25^2 = 2 BN^2 + 337

Or, BN^2 = 144

Thus, BN = 12