Question

In ꯳ABCD, seg AD||seg BC.Diagonal AC and diagonal BD intersect each other in point P. Then show that AP/PD= PC/BP

Answer 1

Given:
AD || BC, diagonal AC and diagonal BD intersect each other at point P.

To prove : AP/PD=PC/BP

Construction :
Draw ST || BC

Proof :
AS/SB=DT/TC..............(1)
[By using property of three || lines and their transversals] 
In ∆’s ABC & DCB we get,
AS/SB=AP/PC..............(2)
DT/TC=PD/BP..............(3)
[By using basic proportionality theorem]
From eq (1),(2) & (3),
AP/PC=PD/BP
i.e. AP/PD=PC/BP

Hence proved ..

HOPE THIS WILL HELP YOU….

Answer 2

Answer:

Step-by-step explanation:

Answer is given in pic..