Question

In figure 1.74, PM=10 cm A(ΔPQS)=100 sq.cm A(ΔQRS)=110 sq.cm then find NR.

Answer 1

Answer:

PM=10 cm A(ΔPQS)=100 sq.cm A(ΔQRS)=110 sq.cm then NR = 11 cm

Step-by-step explanation:

Area of Δ PQS = (1/2) QS * PM

A(ΔPQS)=100  cm²

(1/2) QS * PM = 100

=> (1/2) * QS * 10 = 100

=> QS = 20

Area of Δ QRS = (1/2) QS * PM

A(ΔQRS)=110 cm²

(1/2) QS * NR = 110

=> (1/2) * 20 * NR = 110

=>10 * NR = 110

=> NR = 11 cm

as per fig A(ΔQRS)=150 cm² then NR = 15 cm