Math, asked by adeshbhullar9446, 1 year ago

In adjoining figure, AP⊥BC,AD||BC, then find A(Δ ABC): A(Δ BCD).

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Answered by desiboyz3
21
1:1 will be the answer ,
when two triangle having same base and between same parallel line ,then area of both triangle are equal
Answered by amitnrw
54

Answer:

In adjoining figure, AP⊥BC,AD||BC, then find A(Δ ABC): A(Δ BCD)

1:1

Step-by-step explanation:

Area of Triangle = (1/2) * Base * Height

Area of Triangle Δ ABC  = (1/2) BC * AP

Lets draw a perpendicular DQ from point D at BC line

DQ ║ AP

AD║BC

=> DQ = AP

Area of Δ BDQ = (1/2)(BQ) * DQ

= (1/2)(BC + CQ) * AP

Area of ΔCDQ = (1/2) CQ * DQ

= (1/2)CQ * AP

Area of Δ BCD = Area of Δ BDQ - Area of Δ CDQ

= (1/2)(BC + CQ) * AP -  (1/2)CQ * AP

= (1/2)(BC) * AP

= Area of Triangle Δ ABC

=> A(Δ ABC): A(Δ BCD) :: 1: 1

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