In adjoining figure, AP⊥BC,AD||BC, then find A(Δ ABC): A(Δ BCD).
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1:1 will be the answer ,
when two triangle having same base and between same parallel line ,then area of both triangle are equal
when two triangle having same base and between same parallel line ,then area of both triangle are equal
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Answer:
In adjoining figure, AP⊥BC,AD||BC, then find A(Δ ABC): A(Δ BCD)
1:1
Step-by-step explanation:
Area of Triangle = (1/2) * Base * Height
Area of Triangle Δ ABC = (1/2) BC * AP
Lets draw a perpendicular DQ from point D at BC line
DQ ║ AP
AD║BC
=> DQ = AP
Area of Δ BDQ = (1/2)(BQ) * DQ
= (1/2)(BC + CQ) * AP
Area of ΔCDQ = (1/2) CQ * DQ
= (1/2)CQ * AP
Area of Δ BCD = Area of Δ BDQ - Area of Δ CDQ
= (1/2)(BC + CQ) * AP - (1/2)CQ * AP
= (1/2)(BC) * AP
= Area of Triangle Δ ABC
=> A(Δ ABC): A(Δ BCD) :: 1: 1
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