in adjoining figure find the distance AC
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by Pythagoras theorem
AE^2 + AB^2 = EB^2
AB^2 = EB^2 - AE^2
= 100 - 36
= 64
AB = 8
BC^2 = BD^2 - DC^2
= 169 - 144
= 25
BC = 5
AC = AB + BC
= 8 + 5
= 13
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