Question

in adjoining figure find the distance AC

Answer 1

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Answer 2

by Pythagoras theorem

AE^2 + AB^2 = EB^2

AB^2 = EB^2 - AE^2

         = 100 - 36

         = 64

AB = 8

BC^2 = BD^2 - DC^2

         = 169 - 144

         = 25

BC = 5

AC = AB + BC

     = 8 + 5

     = 13