In adjoining figure
seg PS perpendicular to seg RQ seg QT perpendicular to seg PR.
If RQ = 6, PS = 6 and PR = 12,
then find QT.
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Answer:
Given:
PS ⊥ RQ
QT ⊥ PR
RQ = 6, PS = 6 and PR = 12
With base PR and height QT,
A(△PQR)=½×PR×QT
With base QR and height PS,
A(△PQR)=½×QR×PS
∴A(△PQR)/A(△PQR)=½×PR×QT/½×QR×PS
⇒1=PR×QT/QR×PS
⇒PR×QT=QR×PS
⇒QT=QR×PS/PR
=6×6/12
=3
Hence, the measure of side QT is 3 units.
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