In an AP a=5, d=3 ,an=50 find n and sn
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Answered by
14
Step-by-step explanation:
An = a+ ( n-1) d
50 = 5+(n-1)3
50-5=3n-3
45+3=3n
n=16
Sn=n/2(a+An)
=8(5+50)
=8(55)
Sn =440
HOPE IT WOULD HELP U....
Answered by
0
An = a + (n-1)d
==> 50 = 5 + (n-1) 3
==> 50-5 = (n-1)3
==> 45/3 = n-1
==> 15 = n-1
==> 16 = n
sum formula = n/2 (2a+(n-1)d
===> 16/2 [ 2(5) + (16-1)3 ]
===> 8 [ 10 + 45]
===> 8 [ 55]
===> 440
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