Question

In an area, 2% of families have 5 children each. But 8% have no children at all. Amongst the rest of the families, 18% have 4 children and 27% have only one child. How many families live in the area, if 297 families have either 2 or 3 children each?

Answer 1

Given that,

2%   of families   with 5 Children each

8%   of families with No Children

It indicates,

10%  of total families have either 5 Children or No Children

90% of remaining families considered as total in further given details

18% of 90%  have 4 Children

27% of 90% have 1 Child

It indicates

45% of 90% in total have either 4 Children or 1 Child

55% of 90%  (100% of 90% minus 45% of 90%) is remaining families have either 2 or 3 Children i.e., 297 families

Now calculating with above information start from bottom line,

If 55% of 90% is 297 Families, then 100% of 90% is

⇒ (297/55)*100 = 540 families

if 540 families are 90% then 100% families are

⇒ (540/90)*100 = 600 Families

Total 600 families live in that area.

Answer 2

Answer:

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