in an election to municipal council the votes secured by two candidates are in the ratio 13:19 the elected candidate gets 312 votes more than the second candidate how many votes are secured by the second cadidate
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Answered by
2
The second candidate gets only votes
X+X+312=32x
312=30x
X=312/30
X=1.4
13x=13*1.4=18 votes
X+X+312=32x
312=30x
X=312/30
X=1.4
13x=13*1.4=18 votes
Answered by
11
Hi ,
Let A and B are two contestants ,
ratio of votes secured = 13 : 19
A votes = 13x
B votes = 19x
according to the problem given ,
19x - 13x = 312
6x= 312
x = 312/6
x = 52
Therefore ,
A votes = 13x = 13 × 52 = 676
B votes = 19 × 52 = 988
I hope this helps you.
: )
Let A and B are two contestants ,
ratio of votes secured = 13 : 19
A votes = 13x
B votes = 19x
according to the problem given ,
19x - 13x = 312
6x= 312
x = 312/6
x = 52
Therefore ,
A votes = 13x = 13 × 52 = 676
B votes = 19 × 52 = 988
I hope this helps you.
: )
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