Math, asked by siva59, 1 year ago

in an equilateral triangle ABC d is a point on side BC such that BD = 1 upon 3 BC prove that 9 a d square = 7 a b square

Answers

Answered by MahakYadav1
1
AD^2=7AB^2/9
9AD^2=7AB^2
Hence proved.
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Answered by singhdipanshu2707200
0

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Check your answer please

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