Question

In an examination in which full marks were 500 a got 10%

Answer 1

a got 50 Marks if  a got 10% of 500 full marks

Step-by-step explanation:

In an examination in which full marks were 500 a got 10%

Total Marks = 500

a got = 10 %

10 %  of 500  = (10/100) * 500

= 50

=> a got = 50 Marks

a got 50 Marks if  a got 10% of 500 full marks

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Answer 2

D got 80% marks.

Step-by-step explanation:

Consider the provided information.

In an examination in which full marks were 500, A got 10% less than B. B got 25% more than C. C got 20% less than D. If A got 360 marks, what percentage of full marks was obtained by D ?

It is given that A got 360 marks which are 10% less than B.

Thus B got:

$B=\frac{360\times 100}{100-10}\\B=\frac{360\times 100}{90}\\B=400$

Thus, B got 400 marks.

B Got 25% more than C.

Thus, C got:

$C=\frac{400\times 100}{100+25} \\C=\frac{400\times 100}{125} \\C=320$

Thus, C got 320 marks.

C got 20% less than D.

Thus, D got:

$D=\frac{320\times 100}{100-20} \\C=\frac{320\times 100}{80} \\C=400$

Hence, D got 400 marks.

We need to find the percentage of marks.

Formula of percentage: $\frac{Part}{Whole}=\frac{\%}{100}$

$\frac{400}{500}=\frac{\%}{100}$

$\%=\frac{400}{500}\times 100$

$\%=80$

Hence, D got 80% marks.

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