Question

An energy of 500 j is spent to increase of speed of wheel 60 rpm to 240 rpm calculate the moment of inertia of the wheel

Answer 1

Answer:

300

Explanation:

60+240= 300 500/300 =5/3

Answer 2

The moment of inertia of the wheel is 1.69 kgm²

Given-

• Energy = 500 J
• Initial speed of the wheel = 60 rpm
• Final speed of the wheel = 240 rpm

We know that change in kinetic energy is equals to energy spent.

So,

1/2 I ωf² - 1/2 Iωi² = E where ω is the angular speed. i and f represents for initial and final respectively.

ωf = 240 rpm = 240 × 2 × 3.14/60 = 25.12 rad/ sec

ωi = 60 rpm = 60 × 2 × 3.14/60 = 6.28 rad/sec

By substituting the value we get

1/2 I (25.12² - 6.28²) = 500

I = 1.69 kgm²