Question

In an examination, it is required to get 296 marks out of aggregate marks to pass. a student gets 222 marks and is declared failed by 10% marks. what are the maximum aggregate marks as student can get?

Answer 1

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Let the maximum aggregate marks be x,

According to the question

A student get 222 marks and he is declared as fail by 10% and 296 is required for passing then we get a :

10% of total aggregate is equal to the difference of minimum marks required to number of marks he get

Now,

10% of x = 296 - 222

$\frac{10x}{100} = 296-222\\ \frac{x}{10} = 74\\ x= 74\times 10 \\ x=740$


Total marks will be 740.

Thanks