In an exhibition hall, there are 24 display boards each of length 1m 50cm and breadth 1m. There is a 100m long aluminium strip, which is used to frame these boards.
In the above question, how many square metres of cloth is required to cover all the display boards? What will be the length in m of the cloth used, if its breadth is 120cm?
Answers
Step-by-step explanation:
Step 1: Find the perimeter of each board.
Length =1.5 m and Breadth 1 m
Perimeter of each board = 2 (length + breadth)
=2(1.5+1) m
=(2×2.5) m
=5 m
Step 2: Find number of boards which can be framed
Number of boards which can be framed =
Perimeter of each board
length of aluminum strip
=
5m
100m
=20
Thus, 20 boards can be formed.
Length of aluminum strip required for remaining boards = (Total number of boards - number of boards which can be framed ) × Perimeter of of each board
=(24−20)×5
=(4×5) m
=20 m
∴20 boards can be formed and length of aluminium strip required for remaining boards is 20m