Question

In an experiment, 295 mg of copper is deposited when a current of 500 mA passes for 30 minutes. Find the electrochemical equivalent of copper1

Answer 1

The amount of copper deposited = 295 mg = 0.295 g.

Amount of current passed for 30 minutes = 500 mA = 0.5 ampere.

So, the quantity of charge that is passed = 0.5 x 30 x 60 = 900 Coulombs.

The amount of copper deposited at a charge of 900 coulombs = 0.295 g.

Since 1 Faraday = 96500 coulombs, 96500 coulombs of charge will deposit an amount of copper = 0.295 / 900 x 96500 = 31.6 g

So, the electrochemical equivalent of copper1 = 31.6 g/coulomb.