Physics, asked by prateekpriyadarshi82, 2 days ago

In an experiment, students need to get an upright image of an object using a lens of focal length 25 cm. The experiment was set up by putting the lens and the object at a distance of 10 cm. Students of group A used a convex lens and group B used a concave lens for their experiment. The ratio of magnification obtained by group A and group B is:

A. 3/7
B. 7/3
C. 3
D. 1​

Answers

Answered by nvswathi33
6

Answer:

A is the right answer

PRIYADARSHINI MAM

Explanation:

PLEASE MARK ME AS BRAINLIEST ANSWER

Answered by GulabLachman
0

Given: In an experiment, students need to get an upright image of an object using a lens of focal length 25 cm. The experiment was set up by putting the lens and the object at a distance of 10 cm. Students of group A used a convex lens and group B used a concave lens for their experiment.

To find: The ratio of magnification obtained by group A and group B

Explanation: Let the focal length be f, image distance be v and object distance be u.

For group A, the lens used was a convex lens which has a positive focal length.

f = + 25 cm

u= -10 cm

Using lens formula:

 \frac{1}{f}  =  \frac{1}{v}  -  \frac{1}{u}

 \frac{1}{v }  =  \frac{1}{f}  +  \frac{1}{u}

 \frac{1}{v}  =  \frac{1}{25}   +  \frac{1}{ - 10}

 \frac{1}{v}  =  \frac{2 - 5}{50}

 \frac{1}{v}  =  \frac{ - 3}{50}

v =  \frac{ - 50}{3}

Let magnification produced by group A be m1. The formula for magnification is:

m 1=  \frac{v}{u}

m 1=  \frac{ \frac{ - 50}{3} }{ - 10}

m1 =  \frac{5}{3}

For group B, the lens used was a concave lens which has a negative focal length.

f = - 25 cm

u= -10 cm

Using lens formula:

 \frac{1}{f}  =  \frac{1}{v}  -  \frac{1}{u}

\frac{1}{v }  =  \frac{1}{f}  +  \frac{1}{u}

 \frac{1}{v}  =  \frac{1}{ - 25}   +  \frac{1}{ - 10}

 \frac{1}{v}  =  \frac{ - 2 - 5}{50}

 \frac{1}{v}  =  \frac{ - 7}{50}

v =  \frac{ - 50}{7}

Let magnification produced by group B be m2. The formula for magnification is:

m 2=  \frac{v}{u}

m 2=  \frac{ \frac{ - 50}{7} }{ - 10}

m2 =  \frac{5}{7}

Ratio of magnification of group A and B:

= \frac{m1}{m2}

= \frac{ \frac{5}{3} }{ \frac{5}{7} }

= \frac{7}{3}

Therefore, ratio of magnification is option (b) 7/3.

Similar questions