Question

In an ideal transformer input A.C. voltage is 220 V. Current in secondary coil is 2.5 A If the ratio of number of turns in primary coil and secondary coil is 1 : 10, find
(1) Output voltage
(2) Current in primary coil
(3) Input and output power. [Ans: 2200 V, 25 A, 5500 W]

Answer 1

Answer:

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Answer 2

Answer:

2200 V, 25 A, 5500 W

Explanation:

Given,

(1) Ratio of number of turns in primary and secondary coil, N1:N2= 1:10

voltage in primary turns, V1= 220 V

From the formula,

$\dfrac{V1}{V2}\ =\ \dfrac{N1}{N2}$

$=>\ \dfrac{220}{V2}\ =\ \dfrac{1}{10}$

$=>\ V2\ =\ 2200$

Hence, the output voltage will be 2200 V.

(2) Current in secondary coil, I2 = 2.5 A

From the formula,

$\dfrac{I2}{I1}\ =\ \dfrac{N1}{N2}$

$=>\ \dfrac{2.5}{I1}\ =\ \dfrac{1}{10}$

$=>\ I1\ = 25\ A$

Hence, the current in primary coil is 25 A.

(3). Input power = V1 x I1

                           = 220 x 25

                           = 5500 W

Input power = V1 x I1

                           = 220 x 25

                           = 5500 W

Input power = V1 x I1

                           = 220 x 25

                           = 5500 W

Output power = V2 x I2

                           = 2200 x 2.5

                           = 5500 W

Hence, the input power and output power will be equal to 5500 W.