Question

Find the necessary inductance, if 110 V, 10 W ratting bulb is to be used with 220 V A.C source having frequency 50 Hz. [ Ans. L = 6.67 H]

Answer 1

Dear Student,

◆ Answer -

L = 6.674 H

◆ Explaination -

# Given -

Pb = 10 W

Vb = 110 V

Vs = 220 V

f = 50 Hz

# Solution -

Current flowing through bulb is -

I = Pb/Vb

I = 10/110

I = 1/11 A

Voltage across inductor would be -

V = √(Vs^2 - Vb^2)

V = √(220^2 - 110^2)

V = 110√3

Reactance of the inductor would be -

XL = V/I = 2πfL

L = V / (2πfI)

L = 110√3 / (2 × 3.14 × 50 × 1/11)

L = 6.674 H

Therefore, necessary inductance is 6.674 H.

Thanks dear...