Question

In an orbital maximum number of possible electrons with the quantum numbers n=3 and s=-1/2. Pls answer it's urgent

Answer 1

maximum no of electrons in an orbital 3d and s=-1/2 is 5 electrons

Answer 2

Hey!!

Here is your answer -

When n=3,l=0,1,2 i.e., there are 3s, 3p and 3d orbitals. If all these orbitals are completely occupied as shown in the figure.

Total 18 electrons, 9 electrons with s=+ 1/2 ​and 9 with s=− 1/2

Alternatively, in any n^th orbit, there can be a maximum of 2n^2 electrons. Hence, when n=3, number of maximum electrons =18. Out of these 18 electrons, 9 can have spin − 1/2 and remaining nine with spin =+ 1/2