Question

In an organic compound with molar mass 108 g, c, h, and n are present in the ratio 9: 1: 3.5 by mass. Molecular formula of the compound is:

Answer 1

Molar mass of compound = 108 grams

Total part by weight = 9 + 1 + 3.5 = 13.5

Weight of carbon = (9*108)/13.5 = 72 g

Number of carbon atoms = 72/12 = 6

Weight of hydrogen = (1*108)/13.5 = 8 g

Number of hydrogen atoms = 8/1 = 8

Weight of nitrogen = (3.5*108)/13.5 = 28 g

Number of nitrogen atoms = 28/14 = 2

Hence, molecular formula is C6H8N2