Chemistry, asked by CapyltainNJ3635, 1 year ago

Calculate d ratio of no of sodium atoms in the 3p excited state to d no in d ground state 3s at 2500k.The energy difference b/n excited and ground state is 3.372×10^-12

Answers

Answered by kallurisubhashini435
0

The sodium spectrum is dominated by the bright doublet known as the Sodium D-lines at 588.9950 and 589.5924 nanometers. From the energy level diagram it can be seen that these lines are emitted in a transition from the 3p to the 3s levels. The line at 589.0 has twice the intensity of the line at 589.6 nm. Taking the range from 400-700nm as the nominal visible range, the strongest visible line other than the D-lines is the line at 568.8205 which has an intensity about 0.7% of that of the strongest line.

All other lines are a factor of two or more fainter than that one, so for most practical purposes, all the lightThe illustration at left shows the interference pattern formed by the sodium doublet in a Fabry-Perot interferometer. At right is a sketch of the origin of the sodium doublet.  

Sodium light from an electric pickle! from luminous sodium comes from the D-lines.

Similar questions
Math, 1 year ago