In angel ABC ,A= 70°,B=60° and the bisectors of angel B and angel C meet at o. find (i) angel c and angle boc
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angle C = 180-70+60 = 50 (by Angle Sum Property)
angle OBC = 60/2 = 30 (bisector)
angle OCB = 50/2 = 25 (bisector)
angle BOC = 180 - 30+25 = 125 (by Angle Sum Property)
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