Math, asked by nrupa1879, 9 months ago

In angel ABC ,A= 70°,B=60° and the bisectors of angel B and angel C meet at o. find (i) angel c and angle boc

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Answered by AnshritSingh

1

Answer:

angle C = 180-70+60 = 50 (by Angle Sum Property)

angle OBC = 60/2 = 30 (bisector)

angle OCB = 50/2 = 25 (bisector)

angle BOC = 180 - 30+25 = 125 (by Angle Sum Property)

Answered by p4prashantraj14

0

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