Question

In angle PQR, right angled at Q , if PQ =5 cm and PR =13 cm , then QR is

Answer 1

By Pythagoras Theorem,
${h}^{2} = {b}^{2} + {p}^{2}$
$= > {pr}^{2} = {pq}^{2} + {rq}^{2}$
$= > {13}^{2} = {5}^{2} + {qr}^{2}$
$= > {qr}^{2} = 169 \: - \: 25$
$qr = \sqrt{144}$
$qr = 12cm$
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