Question

a man buys a plot of land at rupees 360000 and sells one third of the plot at a loss of 20% . again he sells two thirds of the plot left at a profit of 25% . at what price should he sell the remaining plot in order to get a profit of 10% on the whole

Answer 1

Ans= 100,000 rupees
process-
one third of 3,60,000 is 1,20,000(3,60,000 divided by 3)
loss = 20% of 1,20,000 = 24,000(1,20,000 divided by 5)
 money sold is cost - loss = 1,20,000 - 24,000 = 96, 000
one third of plot left = one third of 2,40,000(3.60,000 - 1,20,0000) = 80,000(2,40,000 divided by 3)
Therefore two thied of plot is 1,60,000( 2,40,000 - 80,000).
profit of 25% of 1,60,000 = 40,000(1,60,000 divided by 4)
money sold in = cost + profit = 1,60,000 = 40,000 = 2,00,000
to get 105 on the whole he should sell it in 1,00,000(t 296,000  10% of  then subtract it with total money got = 3,60,0000 

Answer 2

$\bold{\large{\underline{\underline{\sf{AnsWer:}}}}}$

The last part of the land should be sold at 150000rs

$\bold{\large{\underline{\underline{\sf{StEp\:by\:stEp\:explanation:}}}}}$

The total price of the land is 360000.

For the first 1/3 part he should get

$\frac{1}{3}$x 360000= 120000rs.

But he sells it at a loss of 20%

The amount of loss is →

$\frac{20}{100}$x120000= 24000rs

Therefore, the amount at which the farmer sold 1/3 of land is →

120000-24000= 96000

Similarly, the next 1/3 of the land was sold at ab amount of

120000+ 25%.

profit(amount)=120000 + 30000=150000rs

To get a total profit of 10% the amount at which the total land should be sold is →

360000+10%profit(amount)= 360000+36000=396000

So the total amount at which he should sell all the three parts should be 396000rs

Therefore,96000+150000+x=396000

Therefore,96000+150000+x=396000

(here x is equal to the amount at which the last 1/3 part of the land should be sold)

Now, 246000+x=396000

. x= 396000-246000= 150000rs.

Therefore the last part of the land should be sold at 150000rs