Question

The density of a solution is 1.84 gm/cc at 35°C and contains 98% H2SO4 by weight. What is the

approax % concentration (w/v) of H2SO4 in solution ?

(1) 1800% (2) 180%

(3) 184% (4) 100%

Answer 1

hope it helps any queries ask me

Answer 2

Answer:

(2) 180%

Explanation:

Given that density = 1.84 gm/cc

Let the volume = 1 cc

So, mass of the solution :    

$Mass\ of\ solution=Density \times {Volume\ of\ solution}$  

$Mass\ of\ solution=1.84\ gm/cc \times {1\ cc}$  

Mass of the solution = 1.84 g

Given that the solution contains 98 % of $H_2SO_4$. So,

Mass of $H_2SO_4$ = 98 % of 1.84 g = $\frac {98}{100}\times 1.84\ g=1.80\ g$

So,

% Concentration= (Mass of $H_2SO_4$ / Volume) × 100

Thus,

$\Rightarrow \frac {1.80}{1}\times 100=180 \%$