Question

In any triangle ABC, if a = 18, b =24 and c=30, find

SinA,SinB and sinC

✓Use cosine rule


#Asap​

Answer 1

HELLO DEAR,

as we know

cosine formula

c² = a² + b² - 2abcosC

similarly,

a² = b² + c² - 2bccosA

b² = a² + c² - 2accosB

now,

given:- a = 18

b =24

c=30

so, (30)² = (18)² + (24)² - 2(18)*(24)cosC

=> 900 = 324 + 576 - 432cosC

=> 900 = 900 - 432cosC

=> 0 = cosC

hence, Cos90° = cosC

so, C = 90°

therefore, sinC = sin90° = 1

now using trignomentric identities,

we get,

sinA = a/c = 18/30 = 3/5

sinB = b/c = 24/30 = 4/5

sinC = 1

I HOPE IT'S HELP DEAR,

THANKS

Answer 2

Step-by-step explanation:

hope it is helpful to you

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