Question

In between two hills of height of 100m and 92m respectively there is a valley of breadth 16m if a vehicle jumps from the first hill to the second what must be its minimum horizontal velocity so that is may not fall into the valley .Take g=9ms

Answer 1

Answer:

Explanation:

the above problem can be solved as

horizontal distance to be travelled is Sy 100 - 92= 8m

vertical distance to be travelled Sx = 16m

let vx be the horizontal velocity =constant here

now vertical sistance equation is Sy=ut+12 gt2

where u is vertical initial velocity

t is time taken to travel 8m i.e., reaching time to land second hill

as vertical initial velocity is 0

so above equation can be written as for time t,

t=2XSyg

so t= 2x89.8 sec.

so t = 1.277 sec.

now taking horizontal distance as Sx= vx X t

16= vx X 1.277

on solving above we get minimum horizontal velocity required to land on second hill as Vx= 12.52 m/sec

Answer 2

Explanation:

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