Question

In class IX of 50 students second language opted by the students is as follows :
Sanskrit - 14
Japanese - 08
French - 12
Urdu - 6
Rest of them opted for German
A student is selected at random . Find the probability that the student .
i) opts for French
ii)does not opts for Japanese
iii) Either opts for Sanskrit or for German.

Please give step wise answers.

Answer 1

I) no. of students opted for French n (E)= 12
total no. of outcomes n (S)=50
probability of student opted for french P (E)=n (E)/n (S)=12/50 = 6/25
ii) probability of students opted gor Japanese P (E1)= 8/ 50=4/25
So tge probability of student not opted for Japanese= 1- P (E1)= 1- 4/25=21/25
iii) no. of favourable outcomes n (E2) =10+14= 24
P (E2)= 24/50= 6/25

Answer 2

Answer:

given there are 50 students ,

so for probabitlity we do  favorable/total

a) opted a french= 12/50=0.24=24/100[if want solve]

b)doesn't japanease means except japanease

so 50-8=42

probability is 42/50=0.84=84/100 [ if want solve]

c) either sanskrit or geman means except sansrit and german

first we have to find german=?

so, 40-50=10

german = 10

now sanskrit+german+14+10=24

so given either sansrit or german so 24-50=26

probability=26/50=0.52=52/100