Question

In complex number, If z1 = 3 + 4i and z2 = 3 – 4i, then find modulus of z1 and z2​

Answer 1

Answer:

both have same modulas and that is equal to 5.

Step-by-step explanation:

see the image

Answer 2

Given:

$z_{1}$ = 3+4i

$z_{2}$ = 3-4i

To Find:

Modules of $z_{1} and z_{2}$

Solution:

A number of the form (a+ ib), where a and b are real numbers.

If z = a + ib

If $z_{1}$ = ($a_{1}$+ i$b_{1}$) and $z_{2}$ = ($a_{2}$ + i$b_{2}$) are two complex numbers, then z1 = z2 implies that z1 = z2 and b1 = b2 i.e., the numbers being equal means their real and imagery parts are separately equal.

Mod of |z| = $\sqrt{a^{2}b^{2} }$

$z_{1}$ = 3+4i

|$z_{1}$| = $\sqrt{3^{2}+4^{2} }$

     = 5

|$z_{2}$| = $\sqrt{3^{2}+(-4)^{2} }$

     = 5

As mentioned above z1 = z2 = 5

Therefore, the modules of $z_{1}$ and $z_{2}$ are 5.