Question

In D ABC, the dividing points ÐA and ÐB intersect at O If ÐC = 70 then measure ÐAOB.​

Answer 1

Answer:

a triangle, the sum of interior angle =180

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Thus, in △ABC ,

∠A+∠B+∠C=180

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∠C=70

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,

Hence,

∠A+∠B=130

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Bisector of ∠A and∠B intersect at point O then

2

∠A

+

2

∠B

=65

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∠OAB+∠OBA=65

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Now, in △OAB,

∠OAB+∠OBA+∠AOB=180

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⇒∠AOB=115

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