Question

In Duma's method 0.52g of an organic compound. On combustion gave

68.6 ml N2 at 270

c and 756 mm pressure. What is the percentage of

nitrogen in the compound.
full solution plz​

Answer 1

Explanation:

Organic compound

DumasMethod

→

N

2

+ other product

volume of N

2

.V=68.6ml

pressure P=76mmHg=1atm

Temprature T=273+27=300k

n=

RT

Pv

=

0.0821×300

1×68.6×10

−3

=2.785×10

−2

amount of nitrogen 2.785×10

−2

×28=0.078

% of nitrogen =

0.52

0.078

=14.93%