Question

In each of the following, determine the value of p for which the given value is a solution of the equation. px^2+√2x-4=0, x=√2​

Answer 1

Answer:

p=1

Step-by-step explanation:

just put x=√2 in equation n u will get it.

Answer 2

Answer:

p = 1

Step-by-step explanation:

px² + √2x - 4 = 0

put x = √2

p(√2)² + √2(√2) - 4 = 0

2p + 2 - 4 = 0

2p - 2 = 0

2p = 2

p = 1