in each of the following, O is the center of the circle.find the size of each lettered angle
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Step-by-step explanation:
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Step-by-step explanation:
Solution:-
Given that
O is the centre of the circle
Let P be the exterior point
PA is the tangent
The angle between the radius of the circle and the tangent at the point of contact is 90°
angle BAP = 90°
So, ∆ BAP is a right angled triangle
Given that
BA and AP are equal
=> angle APB = angle ABP
Since the angles opposite to equal sides are equal.
x = y
We know that
The sum of all angles in a triangle is 180°
=> angle BAP+angle APB+angle ABP
=> 90°+x+y = 180°
=> 90°+x+x = 180°
=> 90°+2x = 180°
=> 2x = 180°-90°
=>2x = 90°
=>x = 90°/2
=>x = 45°
=>y = 45°
Therefore, x = y = 45°
Answer:-
1) x = 45°and y = 45°
Used formulae:-
The angle between the radius of the circle and the tangent at the point of contact is 90°
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