Question

In elcrostatics,v= -E.dr.cos theta,where theta is the angle between what quantity​

Answer 1

Answer:

\mathbf {E} = electric field

S = area of the surface

E = magnitude

\theta = the angle between the electric field lines and the normal (perpendicular) to S

\phi = flux of electric field through a closed cylindrical surface

If the electric field is uniform, the electric flux (ΦE) passing through a surface of vector area S is: ΦE = E⋅S = EScosθ, where E is the magnitude of the electric field (having units of V/m), S is the area of the surface, and θ is the angle betwee

Explanation:

Answer 2

Answer:

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