Question

In Fig. 15.80, ABCD is a trapezium in which AB||DC. Prove that ar(Δ AOD) = ar(Δ BOC).

Answer 1

Step-by-step explanation:

In ∆ADC and ∆BCD

they are on the same base DC and lie between same parallels DC and AB.

so ar(∆ADC)=ar(∆BCD)

Subtracting ar(DOC) from both sides we get

ar(∆ADC)-ar(∆DOC)=ar(∆BCD)-ar(∆DOC)

ar(∆AOD)=ar(∆BOC)

Hope it helps