Question

in fig BD perpendicular to AC. angle DCB=30 and angle EAC=50 find x and y​

Answer 1

Answer:

Step-by-step explanation:

In triangle AFD,  angle  AFD = 180 - (FAD - FDA) = 180 - ( 90 - 50 ) = 40 deg

At point F, angle AFD = BFE = 40 deg

Angle x can be found in two ways. but we do one way.

in triangle EAC, angle AEC = 180 - angle EAC - angle ECA

                             = 180 - 50 - 30 = 100 deg

So angle AEB = x = 180 - 100 deg  = 80 deg

Now in triangle BFE,  x + y + 40 = 180

as x = 80,          80 + y + 40 = 180

y = 60

Answer 2

Answer:

answer is x = 80° ,y=60°