in fig chord AB =chord CD and chord AB perpendicular chord CD .M And N are midpoints of chord CD resp. then prove that quad MONE is square
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Answer:
MONE is a square
Step-by-step explanation:
AB & CD chord intersect at E
O is center of circle
OM ⊥ AB & ON ⊥ CD ( line from center to mid point of chord)
OM² = OA² - AM²
ON² = OD² - DN²
OA = OD = Radius
AM = AB/2 DN = CD/2
AB = CD
=> AM = DN
so OA² - AM² = OD² - DN²
OM² = ON²
=> OM = ON
ON ║ AB as AB ⊥ CD & ON ⊥ CD
OM ║ CD as CD ⊥ AB & OM ⊥ AB
Three angles of MONE are 90° so 4th angle will be 90° also
now OM = ON (already shown) 9 adjacent sides)
So MONE is a square
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