in fig . find x
please help me with steps
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Answer: x=50°
Step-by-step explanation:
Draw a line XE parallel to AB. It is also given that AB II CD.
This ⇒ that CD II XE(as AB II XE and AB II CD).
This also ⇒ that ∠ECD = ∠CEA(alternate interior angles)
AB II XE ⇒ ∠EAB = ∠AEX.
∠EAB=50° ⇒∠AEX=50°
∠ECD=100°⇒∠XEC=100°
∠AEC=∠XEC-∠AEX
=100°-50°
=50°
∴The x=50°
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