Question

les o
ET & ATIVO
be moving with acceleration 2 m/s on horizontal rough surface is shown in four
A block of mass 10 kg, moving
7
→ a= 2 m/s
→F= 40 N
F = 40N
The value of coefficient of kinetic friction is
(2) 0.4
(1) 0.2
(4) 0.1
05​

Answer 1

Answer:

(1)0.2 is the coefficient of kinetic friction.

Explanation:

formula: [f(k)= μk N]

so, we first have to find the value of N and fk to solve the problem:--

N=mg=10*10=100    [taking g=10m/s²]-------------(i)

now, force=mass*a

F-fk=ma

40-fk= 10*2

40-fk=20

-fk=20-40

-fk=-20

fk=20  ---------------(ii)

substitute value of (i) and (ii) in the formula:

we get,

μk=fk/N  

 = 20/100  

 = 0.2

Hope It Helps You..

---PLEASE MARK MY ANSWER AS BRAINLIEST---